x**2-1=0 >>>[−1,1]
x**2-y**2=0 >>>[−y,y]
solve(2y−x-1,4y−x-3) >>>{x:1,y:1}
f''+9f=0 >>>f(x)=C1*sin(3*x)+C2*cos(3*x)
diff(f,x,2)+9f=0 >>>f(x)=C1*sin(3*x)+C2*cos(3*x)
1+2f'(x)/f+3f'(y)/f=0 >>>f(x,y)= F(3*x-2*y)*e-2*x13-3*y13
1+2*diff(f,x,1)/f+3*diff(f,y,1)/f=0 >>>f(x,y)= F(3*x-2*y)*e-2*x13-3*y13